Write a function that, given an integer N (1 ≤ N ≤ 100), returns an array containing N unique integers that sum up to 0. The function can return any such array.

For example, given N = 4, the function could return [1, 0, −3, 2] or [−2, 1, −4, 5]. The answer [1, −1, 1, 3] would be incorrect (because value 1 occurs twice). For N = 3 one of the possible answers is [−1, 0, 1] (but there are many more correct answers).

function uniqueIntegers(N) { result = []; var x = Math.floor(N / 2); var i = 0; if (N % 2 === 0) { // even i = 0; } else { // odd result[0] = 0; i = 1; } while (i < N) { result[i] = x; result[i + 1] = -1 * x; i += 2; x--; } return result; }